(1/z-2)-(1/z+2)=4/(z^2)-4

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Solution for (1/z-2)-(1/z+2)=4/(z^2)-4 equation:



(1/z-2)-(1/z+2)=4/(z^2)-4
We move all terms to the left:
(1/z-2)-(1/z+2)-(4/(z^2)-4)=0
Domain of the equation: z-2)!=0
z∈R
Domain of the equation: z+2)!=0
z∈R
Domain of the equation: z^2-4)!=0
z∈R
We get rid of parentheses
1/z-1/z-4/z^2-2-2+4=0
We calculate fractions
We do not support ezpression: z^3

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